Question

найти производную пжжж))​

Answer 1

Ответ:

$1)y = 3 {x}^{2} - \frac{1}{ {x}^{3} }$

$y' = 6x - ( - 3) {x}^{ - 4} = 6x + \frac{3}{ {x}^{4} }$

$2)y = {( \frac{x}{3} + 7) }^{6}$

$y' = 6 {( \frac{x}{3} + 7) }^{5} \times \frac{1}{3} = 2 {( \frac{x}{3} + 7)}^{2}$

$3)y = {e}^{x} \cos(x)$

$y' = {e}^{x} \cos(x) - {e}^{x} \sin(x)$

$4)y = \frac{ {2}^{x} }{ \sin(x) }$

$y' = \frac{ ln(2) \times {2}^{x} \sin(x) - {2}^{x} \cos(x) }{ { \sin }^{2}(x) }$