Предмет: Алгебра, автор: dashok145

ПОМОГИТЕ ПОЖАЛУЙСТА, ДАЮ 50 БАЛЛОВ

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Автор ответа: NNNLLL54
0

\ \ \left\{\begin{array}{l}\sqrt{x+y-1}=1\\\sqrt{x-y+2}=2y-2\end{array}\right\ \ \ \left\{\begin{array}{l}x+y-1=1^2\\x-y+2=(2y-2)^2\\x+y-1\geq 0\\x-y+2\geq 0\\2y-2\geq 0\end{array}\right\\\\\\\left\{\begin{array}{l}x+y=2\\x-y+2=4y^2-8y+4\\x+y\geq 1\\x-y\geq -2\\2y\geq 2\end{array}\right\ \ \ \left\{\begin{array}{l}x=2-y\\(2-y)-y+2=4y^2-8y+4\\x\geq 1-y\\x\geq y-2\\y\geq 1\end{array}\right

\left\{\begin{array}{l}x=2-y\\4y^2-6y=0\\x\geq 1-y\\x\geq y-2\\y\geq 1\end{array}\right\ \ \ \left\{\begin{array}{l}x=2-y\\2y\, (2y-3)=0\\x\geq 1-y\\x\geq y-2\\y\geq 1\end{array}\right\ \ \ \left\{\begin{array}{l}y_1=0\ ,\ y_2=1,5\\x_1=2\ ,\ x_2=0,5\\x\geq 1-y\\x\geq y-2\\y\geq 1\end{array}\right\\\\\\y\geq 1\ \ \Rightarrow \ \ y=1,5\geq 1\ \ ,\ \ x=0,5\\\\\\x\geq 1-y:\ \ 0,5\geq 1-1,5\ \ ,\ \ 0,5\geq -0,5\ \ verno\\\\x\geq y-2:\ \ 0,5\geq 1,5-2\ \ ,\ \ 0,5\geq -0,5\ \ verno\\\\Ovet:\ \ (\ 0,5\ ;\ 1,5\ ).

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