Question

У(в квадрате)<10у+24

Answer 1

y^2<10y+24
y^2-10y-24<0
y12=(10+-корень(100+96)).2=(10+-14)/2=12 -2
(y-12)(y+2)<0
===============-2===========12===========
++++++++++++++      ---------------          +++++++
y=(-2 12)