Question

30 баллов, помогите срочно

Answer 1

Ответ:

$\left\{\begin{array}{l}(x+y)^2+3(x+y)+2=0\\(x-y)^2-2(x-y)=3\end{array}\right\ \ \left\{\begin{array}{l}t=x+y\\p=x-y\end{array}\right\ \ \left\{\begin{array}{l}t^2+3t+2=0\\p^2-2p-3=0\end{array}\right\\\\\\\left\{\begin{array}{l}t_1=-2\ ,\ t_2=-1\\p_1=-1\ ,\ p_2=3\end{array}\right$

$a)\ \ \left\{\begin{array}{l}x+y=-2\\x-y=-1\end{array}\right\ \ \left\{\begin{array}{l}2x=-3\\2y=-1\end{array}\right\ \ \left\{\begin{array}{l}x=-1,5\\y=-0,5\end{array}\right\\\\\\b)\ \ \left\{\begin{array}{l}x+y=-2\\x-y=3\end{array}\right\ \ \left\{\begin{array}{l}2x=1\\2y=-5\end{array}\right\ \ \left\{\begin{array}{l}x=0,5\\y=-2,5\end{array}\right$

$c)\ \ \left\{\begin{array}{l}x+y=-1\\x-y=-1\end{array}\right\ \ \left\{\begin{array}{l}2x=-2\\2y=0\end{array}\right\ \ \left\{\begin{array}{l}x=-1\\y=0\end{array}\right\\\\\\d)\ \ \left\{\begin{array}{l}x+y=-1\\x-y=3\end{array}\right\ \ \left\{\begin{array}{l}2x=2\\2y=-4\end{array}\right\ \ \left\{\begin{array}{l}x=1\\y=-2\end{array}\right\\\\\\Otvet:\ \ (-1,5\ ;\ -0,5)\ ,\ (\ 0,5\ ;\ -2,5)\ ,\ (-1\, ;\, 0)\ ,\ (\, 1\, ;-2\, )\ .$