Предмет: Математика, автор: ewgescha

Площадь прямоугольника 616м^2, а его длина 28м. Найдите площадь такого квадрата , у которого периметр равен периметру прямоугольника.

Ответы

Автор ответа: Нина111

1.Ширина прямоугольника 616/28=22(м)

2,Периметр прямоугольника 2(28+22)=100(м)

3,Доина стороны квадрата 100/4=25(м)

4,Площадь квадрата 25*25=625(м2)

Автор ответа: funnyann

S=a*b

28*a=616

a=616/28=22

Pпр=(a+b)*2

Pпр=(28+22)*2=100

Pкв=Pпр=100

Pкв=4*a

Pкв=100/4=25,значит a=25

Sкв=a*a

Sкв=625

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