Question

(1-log4 36)(1log2 36 )

Answer 1

Ответ:

1–log2 12)(1–log6 12)=(log2 2–log2 12)(log6 6–log6 12)=

log2 2/12·log6 6/12=log2 1/6·log6 1/2=log2 6–1·log6 2–1 =

= (–1)·log2 6 × (–1)log6 2 = log2 6 × log6 2 = log2 2 = 1