Question

Решите систему уравнений

Answer 1

$\left \{ {{y=-2x^{2}+4x+3 } \atop {y=-2}} \right. \\\\\left \{ {{-2=-2x^{2}+4x+3 } \atop {y=-2}} \right.\\\\\left \{ {{-2x^{2}+4x+5=0 } \atop {y=-2}} \right.\\\\-2x^{2}+4x+5=0\\\\2x^{2}-4x-5=0\\\\ \frac{D}{4}=(-\frac{4}{2})^{2}-2*(-5)=4+10=14\\\\x_{1}=\frac{2-\sqrt{14}}{2}\\\\x_{2}=\frac{2+\sqrt{14}}{2}\\\\Otvet:\boxed{(\frac{2-\sqrt{14}}{2};-2),(\frac{2+\sqrt{14}}{2};-2)}$