Question

Решить уравнение ( 2х^2 +7x +3):( х^2 - 9) =1​

Answer 1

Ответ:

( 2х^2 +7x +3):( х^2 - 9) =1

Одз: x²-9=0

x≠-3

x≠3

$\frac{2x {}^{2} + 7x + 3 }{x {}^{2} - 9} = 1$

$\frac{2x {}^{2} + 6x + x + 3 }{(x - 3)(x + 3)} = 1$

$\frac{(x + 3)(2x + 1)}{(x - 3)(x + 3)} = 1$

$\frac{2x + 1}{x - 3} = 1$

2x+1=x-3

2x-x+1=-3

x=-3-1

x=-4