Question

log3(x)+log9(x)+log27(x)<22/3

Answer 1

Пусть log₃x=a 

$<var>log_{3}x=a x=3^{a}; log_{9}x=log_{9}3^{a}=frac{a}{2}\ log_{27}x=log_{27}3^{a}=frac{a}{3}\ a+frac{a}{2}+frac{a}{3}<frac{22}{3}\ frac{11a}{6}<frac{22}{3}\ a<4; log_{3}x<4; 0<x<81$