Question

Помогите пожалуйста я вас очень прошу решить с дробями .
Решите примеры заменив данные дроби дробями с одинаковыми знаменателями .
1 2/9+5/6; 3/4+8 11/12; 5/6+7/8; 10 3/8+9/10; 10 11/12-5/8; 13 11/16 - 4 3/4; 6 - 3 8/9; 20 1/50- 19/20.​

Answer 1

$1)1 \frac{2}{9} + \frac{5}{6} = 1 \frac{4}{18} + \frac{15}{18} = 1 \frac{19}{18} = 2 \frac{1}{18}$

$2) \frac{3}{4} + 8 \frac{11}{12} = \frac{9}{12} + 8 \frac{11}{12} = 8 \frac{20}{12} = 9 \frac{8}{12} = 9 \frac{2}{3}$

$3) \frac{5}{6} + \frac{7}{8} = \frac{20}{24} + \frac{21}{24} = \frac{41}{24} = 1 \frac{17}{24}$

$4)10 \frac{3}{8} + \frac{9}{10} = 10 \frac{15}{40} + \frac{36}{40} = 10\frac{51}{40} = 11 \frac{11}{40}$

$5)10 \frac{11}{12} - \frac{5}{8} = 10 \frac{22}{24} - \frac{15}{24} = 10 \frac{7}{24}$

$6)13 \frac{11}{16} - 4 \frac{3}{4} = 13 \frac{11}{16} - 4 \frac{12}{16} = 12 \frac{27}{16} - 4 \frac{12}{16} = 8 \frac{15}{16}$

$7)6 - 3 \frac{8}{9} = 5 \frac{9}{9} - 3 \frac{8}{9} = 2 \frac{1}{9}$

$8)20 \frac{1}{50} - \frac{19}{20} = 20 \frac{2}{100} - \frac{95}{100} = 19 \frac{102}{100} - \frac{95}{100} = 19 \frac{7}{100}$