Question

Нужна помощь срочно

Answer 1

Ответ:

$1) {2}^{x + 3} - {2}^{x + 1} = 12 \\ {2}^{x + 1} ( {2}^{2} - 1) = 12 \\ {2}^{x + 1} = 4 \\ x + 1 = 2 \\ x = 1$

$2) {3}^{2x} - 2 \times {3}^{2x - 1} - 2 \times {3}^{2x - 2} = 1 \\ {3}^{2x - 2} ( {3}^{2} - 2 \times 3 - 2) = 1 \\ {3}^{2x - 2} \times (9 - 6 - 2) = 1 \\ {3}^{2x - 2} \times 1 = 1 \\ \\ 2x - 2 = 0 \\ x = 1$

$3) {3}^{2 + x} + {3}^{x} = 10 \\ {3}^{x} ( {3}^{2} + 1) = 10 \\ {3}^{x} \times 10 = 10 \\ {3}^{x} = 1 \\ x = 0$