Question

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Answer 1

$\dfrac{\frac{x}3+\frac14}{6\frac34} +\dfrac23=1 \\\\\\ \dfrac{4x+3}{12}:\dfrac{27}4=1-\dfrac23\\\\\\ \dfrac{4x+3}{12}\cdot\dfrac4{27}=\dfrac13\\\\\dfrac{4x+3}{81}=\dfrac13\\\\3(4x+3)=81\\12x=72\\x=6$