Question

1 1
х3 + 3х6 - 4 = 0.​

Answer 1

Объяснение:

${x}^{3} = t \\ 3 {t}^{2} + t - 4 = 0 \\ t1 = - \frac{4}{3} \: \: t2 = 1 \\ 1) \: x ^{3} = 1 \: 2) {x}^{3} = - \frac{4}{3} \\ 1) \: x = 1 \: 2) x = \sqrt[3]{ - \frac{4}{3} }$