Question

помогите пожалуйста с сор по математике​

Answer 1

Ответ:

$1) \: 1 \frac{5}{14} + 1 \frac{5}{7} = \frac{19}{14} + \frac{12}{7} = \frac{19 + 24}{14} = \frac{43}{14}$

$2) \: 5 \frac{5}{9} - 4 \frac{5}{12} = \frac{50}{9} - \frac{53}{12} = \frac{200 - 159}{36} = \frac{41}{36}$

$3) \: 4 - 1 \frac{41}{42} = \frac{168}{42} - \frac{83}{42} = \frac{85}{42}$

$4) \: 5 \frac{2}{3} - 3 = \frac{17}{3} - \frac{9}{3} = \frac{8}{3}$

$5) \: 11 \frac{7}{8} - \frac{11}{12} = \frac{95}{8} - \frac{11}{12} = \frac{285 - 22}{24} = \frac{263}{24}$

Answer 2

Ответ:

1)1

14

5

+1

7

5

=

14

19

+

7

12

=

14

19+24

=

14

43

2) \: 5 \frac{5}{9} - 4 \frac{5}{12} = \frac{50}{9} - \frac{53}{12} = \frac{200 - 159}{36} = \frac{41}{36}2)5

9

5

−4

12

5

=

9

50

−

12

53

=

36

200−159

=

36

41

3) \: 4 - 1 \frac{41}{42} = \frac{168}{42} - \frac{83}{42} = \frac{85}{42}3)4−1

42

41

=

42

168

−

42

83

=

42

85

4) \: 5 \frac{2}{3} - 3 = \frac{17}{3} - \frac{9}{3} = \frac{8}{3}4)5

3

2

−3=

3

17

−

3

9

=

3

8

5) \: 11 \frac{7}{8} - \frac{11}{12} = \frac{95}{8} - \frac{11}{12} = \frac{285 - 22}{24} = \frac{263}{24}5)11

8

7

−

12

11

=

8

95

−

12

11

=

24

285−22

=

24

263