Question

Z1 = 3-4i
Z2 = 2+i  

  

Найдите числа: Z1+Z2 ; Z1-Z2 ; Z1*Z2 ; Z1/Z2 

Answer 1

$z_1 = 3-4i ;z_2 = 2+i \z_1+z_2=3-4i+2+i=5-3i\z_1-z_2=3-4i-2-i=1-5i\z_1*z_2=(3-4i)(2+i)=6+3i-8i-4i^2=10-5i\frac{z_1}{z_2}=frac{3-4i}{2+i}*frac{2-i}{2-i}=frac{(3-4i)(2-i)}{4-i^2}=frac{6-3i-8i+4i^2}{5}=frac{2-11i}{5}$