Предмет: Алгебра, автор: valeriaoliferovskaa

Установите соответствие между функциями и их графиками:

у=-3х-6

у=3х-6

у=-3х+6

Приложения:

Ответы

Автор ответа: ssuper99999

5

Функция прямой вида y=kx+b, зависит от углового коэффициента (к), если k < 0, то график такой функции расположен в 2 и 4 четвертях, при к=0 график функции параллелен оси ox, иначе если x>0, то график такой функции расположен в 1 и 3 четвертях. В то время как b показывает пересечение графика функции с осью oy.

Тогда у=-3х+6 с первой картинкой 3-1

у=3x-6 с нижней картинкой 1-3

Тогда 2-2

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