Question

Решите только 5 Задание

Answer 1

Объяснение:

5.

$x_1=3+\sqrt{5}\ \ \ \ x_2=3-\sqrt{5}\ \ \ \ x^2+bx+c=0\\\left \{ {{b=-(x_1+x_2)} \atop {c=x_1*x_2}} \right. \ \ \ \ \left \{ {{b=-(3+\sqrt{5}+3-\sqrt{5} )} \atop {c=(3+\sqrt{5})*(3-\sqrt{5}) }} \right.\ \ \ \ \left \{ {{b=-6} \atop {c=3^2-(\sqrt{5})^2 }} \right.\ \ \ \ \left \{ {{b=-6} \atop {c=9-5=4}} \right. . \\x^2-6x+4=0.$

Ответ: x²-6x+4=0.