Question

Решите систему:

2х+у=1;

2х^2+ху+у^2=1

Answer 1

y=1-2x
2x^2+x-2x^2+1+4x^2=1

4x^2+1=0
x(4x+1)=0
x=0 или 4x+1=0
x=-1/4