Question

{2(y+3)-(y-3)<4
{6y>3(y+1)-1
Система неравенств,решить подробно.​

Answer 1

Ответ:

$y\in\emptyset$

Объяснение:

$\left\{\begin{array}{l}2(y+3)-(y-3)<4\\6y>3(y+1)-1\end{array}\right\\\\\\\left\{\begin{array}{l}2y+6-y+3-4<0\\6y-3y-3+1>0\end{array}\right\\\\\\\left\{\begin{array}{l}y+5<0\\3y-2>0\end{array}\right\\\\\\\left\{\begin{array}{l}y<-5\\y>\frac{2}{3} \end{array}\right\\\\\\\left\{\begin{array}{l}y\in(-\infty;\;-5)\\y\in(\frac{2}{3};\;+\infty) \end{array}\right\\\\\\y\in\emptyset$