Question

Помогите срочно даю 20 баллов

Answer 1

Ответ:

$AB = \sqrt{41} \\\\AC = \sqrt{123} \\\\BC = \sqrt{26}$

Объяснение:

$A(1;\;1;\;2),\,B(5;\;4;\;6),\,C(8;\;8;\;7)\\\\AB = \sqrt{(5-1)^2+(4-1)^2+(6-2)^2} = \sqrt{16+9+16} = \sqrt{41} \\\\AC = \sqrt{(8-1)^2+(8-1)^2+(7-2)^2}=\sqrt{49+49+25} = \sqrt{123} \\\\BC = \sqrt{(8-5)^2+(8-4)^2+(7-6)^2} = \sqrt{9+16+1} = \sqrt{26}$