Question

ПОМОГИТЕ СРОЧНО!!! ПОМОГИТЕ

Answer 1

Ответ:   r = 12 .

$5x^2-16x+r=0\ \ ,\ \ \ x_1=2\ \ \ \ \to \ \ \ \left\{\begin{array}{l}x_1+x_2=\dfrac{16}{5}\\x_1\cdot x_2=\dfrac{r}{5}\end{array}\right\ \ \ (teorema\ Vieta)\\\\\\ \left\{\begin{array}{l}2+x_2=\dfrac{16}{5}\\2\cdot x_2=\dfrac{r}{5}\end{array}\right\ \ \left\{\begin{array}{l}x_2=\dfrac{6}{5}\\2\cdot \dfrac{6}{5}=\dfrac{r}{5}\end{array}\right\ \ \ \to \ \ \ r=12$