Question

m( CH3COOH ) = 50г. 

m ( CH3OH ) = 18г.

Найти m эфира

Answer 1

рекция: ch3cooh+ch3oh = ch3cooch3 + h2o Условия н2so4 концентрир и темпиратура

ню сh3сooh = 50/60 =0.834

M(ch3cooh) = 12+3+12+32+1=60

nu ch3oh = 18/32=0.56

M(ch3oh)=12+3+16+1=32

ch3cooh в избытке

ню сн3соосн3 по пропорции = 0,56

M ch3cooch3 = 12+3+12+16+16+12+3=74

m ch3cooch3 = 74*0.56=41.44

должно быть так