Question

Помогите решить ...............................

Answer 1

Ответ:

$1)f'(x) = 2x + \frac{1}{2} {(x + 2)}^{ - \frac{1}{2} } = 2x + \frac{1}{2 \sqrt{x + 2} } \\ f"( - 1) = - 2 + \frac{1}{2 \sqrt{1} } = \frac{1}{2} - 2 = - 1.5$

$2)f'(x) = 3 {x}^{2} - \frac{1}{2 \sqrt{x + 5} }$

$f'( - 1) = 3 - \frac{1}{2 \times 2} = 3 - \frac{1}{4} = 2 \frac{3}{4} = 2.75$

$3)f'(x) = 2 \sqrt{2} x + \frac{1}{2 \sqrt{x + 2} } - \sqrt{2} \\ f'( - 1) = - 2 \sqrt{2} + \frac{1}{2} - \sqrt{2} = - 3 \sqrt{2} + \frac{1}{2}$