Question

Log3 27

Log1/2 4

Log5 1

Log8 2

Answer 1

$log_{3}27=log_{3}3^3=3log_{3}3=3*1=3\\log_{ frac{1}{2}}4=-log_{2}2^2=-2log_{2}2=-1*1=-2\\log_{5}1=log_{5}5^0=0\\log_{8}2=log_{2^3}2= frac{1}{3}log_{2}2= frac{1}{3}*1= frac{1}{3}$