Question

Помогите пожалуйста решить
$\tan {}^{2} ( \beta ) \times \cot {}^{2} ( \beta ) - \sin {}^{2} ( \beta )$
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Answer 1

Объяснение:

$tan^2(\beta )*cot^2(\beta )-sin^2(\beta )=(tg(\beta )*cot(\beta ))^2-sin^2(\beta )=\\=(\frac{sin(\beta )}{cos(\beta )}*\frac{cos(\beta )}{sin(\beta )})^2-sin^2(\beta )=1^2-sin^2(\beta )=1-sin^2(\beta )=cos^2(\beta ).$