Question

Буду благодарна за помощь ​

Answer 1

$\frac{18k + 9kz}{k(8 - 2 {z}^{2}) } \times {k}^{3} = \frac{k {}^{3}(18 + 9z )}{8 - 2z {}^{2} } = \frac{ {0.1}^{3} (18 + 9 \times ( - 2.5))}{8 - 2 \times ( - 2.5) {}^{2} } = \frac{ - 0.0045}{ - 4.5} = 0.001$