Question

xy+x=56 xy+y=54 решить систему уравнений

Answer 1

$[tex] xy+x=56 \ xy+y=54 \ (xy+x)-(xy+y)=56-54 \ x-y=2 \ x=y+2 \ (y+2)y+y-54=0 \ y^2+2y+y-54=0 \ y^2+3y-54=0 \ D=9+54*4=225 \ y_{1,2} = frac{-3б15}{2} \ y_1 = frac{-3+15}{2} = 6 \ y_2 = frac{-3-15}{2} = - 9 \ x_1 = 6+2 = 8 \ x_2 = -9+2 = -7 \ Answer quad {y=6; x=8} ; {y=-9; x=-7}$