Question

Решить систему уравнений
{y-3x=1,
{x²-2xy+y²=9​

Answer 1

Объяснение:

$\left \{ {{y-3x=1} \atop {x^2-2xy+y^2=9}} \right.\ \ \ \ \left \{ {{y=3x+1} \atop {(x-y)^2=9}} \right. \ \ \ \ \left \{ {{y=3x+1} \atop {(x-3x-1)^2-9=0}} \right. \ \ \ \ \left \{ {{y=3x+1} \atop ({-2x-1)^2}-3^2=0} \right. \\\left \{ {{y=3x+1} \atop {(-2x-1+3)*(-2x-1-3)=0}} \right. \ \ \ \ \left \{ {{y=3x+1} \atop {(-2x+2)*(-2x-4)=0}} \right. \ \ \ \ \left \{ {{y_1=4\ \ \ \ y_2=-5} \atop {x_1=1\ \ \ \ x_2=-2}} \right. .$

Ответ: (1;4), (-2;-5).