Question

РЕШИТЕ ПЖ
(х-3)^4(х+2)^5(х-7)^2(х-10)>0

Answer 1

Ответ:

$\underbrace {(x-3)^4}_{\geq 0}(x+2)^5\underbrace {(x-7)^2}_{\geq 0}(x-10)>0\\\\\\znaki:\ \ \ +++(-2)---(3)---(7)---(10)+++\\\\\\x\in (-\infty \, ;-2\, )\cup (\ 10\ ;+\infty \, )$