Question

х²-9х+18=0 решить с помощью теоремы Виета​

Answer 1

Ответ:

${x}^{2} - 9x + 18 = 0 \\ x1 + x2 = - q \\ x1 \times x2 = p \\ \\ x1 + x2 = - ( - 9) \\ x1 \times x2 = 18 \\ \\ x1 + x2 = 9 \\ x1 \times x2 = 18 \\ \\ 3 + 6 = 9 \\ 3 \times 6 = 18 \\ \\ x1 = 3 \\ x2 = 6$