Question

(2y3+3y2-7)-(5+3y+y3)=3y2+y3-5y

Решите уравнение ​

Answer 1

Ответ:

Объяснение:

$2y^3+3y^2-7-5-3y-y^3=3y^2+y^3-5y$

$2y^3-y^3-y^3+3y^2-3y^2-7-5-3y+5y=0$

$-12+2y=0$

$y=6$

Answer 2

$(2 {y}^{3} + 3 {y}^{2} - 7) - (5 + 3y + {y}^{3} ) = 3 {y}^{2} + {y}^{3} - 5y \\ {y}^{3} + 3 {y}^{2} - 3y - 12 = 3 {y}^{2} + {y}^{3} - 5y \\ 2y = 12 \\ y = 6$