Предмет: Химия, автор: danek7233

В раствор, содержащий 196 г серной кислоты, поместили избыток магния.
Вычислите объем выделившегося газа (н.у.)
С РЕШЕНИЕМ ​

Ответы

Автор ответа: zhenkapechenka6
12

Ответ:

m(р-ра H2SO4)= 196 г

V(H2) - ?

 

H2SO4 + Mg(изб.) = MgSO4 + H2(стрелка вверх)

n(р-ра H2SO4)=m/M=196/(1*2+32+16*4)= 2 моль

n(H2)=n(р-ра H2SO4)=2 моль

V(H2)= Vm* n= 2* 22,4 = 44,8 литров

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Объяснение:

n - кол-во моль

M - молярная масса

m - масса

V - объем

Vm - молярный объем (22,4 моль/л)

danek7233: оаоаооа, спасибо
zhenkapechenka6: та на здоровье родной
danek7233: поможешь ещё? :D
danek7233: я 0 в химии просто
zhenkapechenka6: конечн
zhenkapechenka6: я частенько уже на твои задания отвечаю
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