Question

решите неравенство (9кл)
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Answer 1

$\left \{ {{x^{2} -13x+30<0} \atop {x^{2} +7x+10>0}} \right.$

$\left \{ {{x^{2} -13x+30>0} \atop {x^{2} +7x+10<0}} \right.$

$x(3;10)$

$x(-5;-2)$

Ответ:

x Э (-5;-2) U (3;10)