Question

Вычислить f'(x0) ???​

Answer 1

f'(x)= -7е⁻⁷ˣ⁻⁶+(3*(1/3)е^(∛(x²+3x+3))(2x+3))/(x²+3x+3)²/³

f'(-1)= -7е⁷⁻⁶+е^(∛(1-3+3))(-2+3))/(1-3+3)²/³=-7е+е=-6е