Question

Помогите пожалуйста! выг@дн@ -^-

Answer 1

$Sin<A=\frac{1}{5} \\\\CB=4\sqrt{6} \\\\Sin<A=\frac{CB}{AB} \\\\AB=\frac{CB}{Sin<A}= 4\sqrt{6} :\frac{1}{5}=4\sqrt{6}*5=20\sqrt{6}\\\\AC=\sqrt{AB^{2}-CB^{2}} =\sqrt{(20\sqrt{6})^{2}-(4\sqrt{6})^2} =\sqrt{(20\sqrt{6}-4\sqrt{6})(20\sqrt{6}+4\sqrt{6})}=\\\\=\sqrt{16\sqrt{6}*24\sqrt{6}}=\sqrt{16*6*6*4} =4*6*2=48\\\\Otvet:\boxed{AB=20\sqrt{6} ;AC=48}$