Question

(2y-3)(3y+1)+2(y-5)(y+5)=2(1-2y)+6y

Answer 1

(2у-3)(3у+1)+2(у-5)(у+5)=2(1-2у)+6у

6у^2+2y-9y-3+2(y^2+5y-5y-25)=2-4y+6y

6y^2+2y-9y-3+2y^2-50-2-2y=0

8y^2-9y-49=0