Question

Срочно помогите пж!!!!!!!!!!!!
log0,7(2x-3)>=log0,7(3-x)
log0,3x+log0,3(x-3)=log0,3(8-x)
3lgx^2-lg^2(-x)-9=0

Answer 1

1. 2-3x≤3-x

-3x +x≤ 1

-2x≤1

x≥ -0.5

2.

(2log3-2)x=10log3-10

x= 10log3-10/ 2log3-1

x=5