Question

С 630-637(в, г) (с решением)
Помогите, все на фоте

Answer 1

Ответ:

630)

В) $\sqrt{2^{12}} =2^6=64$

Г) $\sqrt{(-5)^2} =5$

631)

В) $\sqrt{7^2*2^6} =7*2^3=7*8=56$

Г) $\sqrt{3^4*5^2} =3^2*5=9*5=45$

632)

В) $-3\sqrt{2^6} =-3*2^3=-3*8=-24$

Г) $5\sqrt{(-2)^8} =5*(-2)^4=5*2^4=5*16=80$

633)

В) $\sqrt{49c^4} =\sqrt{49} \sqrt{c^4} =\sqrt{7^2} c^2=7c^2$

Г)  $\sqrt{81d^6} =\sqrt{81} \sqrt{d^6} =\sqrt{9^2} d^3=9d^3$

634)

В) $-0.1\sqrt{100z^8} =-0.1*10z^4=-z^4$

Г) $-\sqrt{0.25t^2} =-\sqrt{0.25} t=-\sqrt{\frac{1}{4} } t=-\frac{1}{2} t=-0.5t$

635)

В) $\sqrt{m^{12}n^{16}} =\sqrt{m^{12}} \sqrt{n^{16}} =m^6n^8$

Г) $\sqrt{p^8q^{10}} =\sqrt{p^8} \sqrt{q^{10}} =p^4q^5$

636)

В) $\sqrt{36m^2n^8} =\sqrt{36} \sqrt{m^2} \sqrt{n^8} =\sqrt{6^2} mn^4=6mn^4$

Г) $\sqrt{\frac{1}{4} r^{18}s^2} =\sqrt{\frac{1}{4} } \sqrt{r^{18}} \sqrt{s^2} =\frac{\sqrt{1} }{\sqrt{4} } *r^9s=\frac{1}{\sqrt{2^2} } *r^9s=\frac{1}{2} r^9s$

637)

В) $\sqrt{\frac{49a^{18}}{81b^6} } =\frac{\sqrt{49a^{18}} }{\sqrt{81b^6} } =\frac{\sqrt{49}\sqrt{a^{18}} }{\sqrt{81}\sqrt{b^6} } =\frac{\sqrt{7^2}a^9 }{\sqrt{9^2} b^3} =\frac{7a^9}{9b^3}$

Г) $\sqrt{\frac{576a^{12}}{25b^{26}} } =\frac{\sqrt{576a^{12}} }{\sqrt{25b^{26}} } =\frac{\sqrt{576}\sqrt{a^{12}} }{\sqrt{25} \sqrt{b^{26}} } =\frac{\sqrt{24^2}a^6 }{\sqrt{5^2} b^{13}} =\frac{24a^6}{5b^{13}}$