Question

Решите пожалуйста 16 номер!!!!!

Answer 1

Ответ:

$f(x) = \frac{x - 2}{ {x}^{3} - 8 }$

$f'(x) = \frac{1 \times ( {x}^{3} - 8) - 3 {x}^{2} \times (x - 2) }{ {( {x}^{3} - 8)}^{2} } = \frac{ {x}^{3} - 8 - 3 {x}^{3} + 6 {x}^{2} }{ {( {x}^{3} - 8) }^{2} } = \frac{ - 2 {x}^{3} + 6 {x}^{2} - 8 }{ {( {x}^{3} - 8) }^{2} }$