Question

Log от основания 2 умножить на (х+2) +  log от 2 умножить на (х-3) = 1

Answer 1

log2 (x+2) + log2 (x-3) = 1
log2( (x+2)*(x-3)) = 1
log2( x^2 -3x +2x- 6) =log2(2)
x^2 -x - 6 =2
x^2 -x - 8 =0

D= (-1)^2 - 4*1*(-8) = 33
x1 = (-(-1) + ((33)^(1/2)))/2 = (1+sqrt(33))/2
x2 = (-(-1) - ((33)^(1/2)))/2 = (1-sqrt(33))/2