Question

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Answer 1

Ответ:

4) $x^3-5x^2-x+5=0$

$x^2*(x-5)-(x-5)=0$

$(x-5)*(x^2-1)=0$

$x-5=0$

$x^2-1=0$

x₁ = -1, x₂ = 1, x₃ = 5

5) $\frac{x^2-3x+2}{2-x} =0$

$x\neq 2$

$\frac{x^2-x-2x+2}{-(x-2)} =0$

$\frac{x*(x-1)-2(x-1)}{-(x-2)} =0$

$\frac{(x-1)*(x-2)}{-(x-2)} =0$

$(x-1)*(-1)=0$

$-x+1=0$

$-x=-1$

x = 1