Question

311,Пожалуйста помогите

Answer 1

Ответ:

1) $3x^2-(2x^2-8x)-(x^2-3)=x$

$3x^2-2x^2+8x-x^2+3=x$

$0+8x+3=x$

$8x+3=x$

$8x-x=-3$

$7x=-3$

x = $-\frac{3}{7}$

2) $12-(6-9x-x^2)=x^2+5x-14$

$12-6+9x+x^2=x^2+5x-14$

$12-6+9x=5x-14$

$6+9x=5x-14$

$9x-5x=-14-6$

$4x=-20$

x= -5

3) $4y^3-(4y^3-8y)-(6y+3)=7$

$4y^3-4y^3+8y-6y-3=7$

$2y-3=7$

$2y=7+3$

$2y=10$

y = 5

4) $(y^2-4y-17)-(6y^2-3y-8)=1-y-5y^2$

$y^2=4y-17-6y^2+3y+8=1-y-5y^2$

$-5y^2-y-9=1-y-5y^2$

$-9=1$

y ∈ ∅