Question

СРООООЧНО!! ПОМОГИТЕ ПРОШУУ!!

Answer 1

Ответ:

$\frac{4x-3}{3-2x} -\frac{4+5x}{3+2x} -\frac{3+x-10x^{2} }{4x^{2} -9} =\frac{4x-3}{-(2x-3)} -\frac{4+5x}{3+2x} -\frac{3+x-10x^{2} }{(2x-3)(2x+3)} =-\frac{4x-3}{2x-3} -\frac{4+5x}{3+2x} -\frac{3+x-10x^{2} }{(2x-3)(2x+3)} =-\frac{(3+2x)(4x-3)+(2x-3)(4+5x)+3+x-10x^{2} }{(2x-3)(3+2x)} =-\frac{12x-9+8x+10x^{2} -12-15x+3+x-10x^{2} }{(2x-3)(3+2x)} =-\frac{0-18+8x^{2} }{(2x-3)(3+2x)} =-\frac{8x^{2} -18} {(2x-3)(3+2x)}=-\frac{2(4x^{2} -9)}{(2x-3)(3+2x)}=-\frac{2(2x-3)(3+2x)}{(2x-3)(3+2x)}=-2$