Question

посогиет решить срочно​

Answer 1

Ответ:

$a)f'(x) = 6 {x}^{5} + 12 {x}^{3}$

$b)f'(x) = - 4 {x}^{ - 3} = - \frac{4}{ {x}^{3} }$

$c)f'(x) = \frac{1}{4 - 5x} \times ( - 5) = - \frac{5}{4 - 5x}$

$d)f'(x) = {e}^{x} (6x - 2) + {e}^{x} \times 6 = {e}^{x} (6x - 2 + 6) = {e}^{x} (6x - 4)$