Question

кто знает как решать?​

Answer 1

$2a {}^{4n - 3} + \frac{a {}^{n + 4} + 4a {}^{n} - 4a {}^{n + 2} }{a {}^{3} } \div \frac{a {}^{2} - 2 }{a {}^{3n} } = 2a {}^{4n - 3} + \frac{a {}^{n} \times (a {}^{4} + 4 - 4a {}^{2} ) }{a {}^{3} } \times \frac{a {}^{3n} }{a {}^{2} - 2 } = 2a {}^{4n - 3} + a {}^{n - 3} \times (a {}^{4} - 4a {}^{2} + 4) \times \frac{a {}^{3n} }{a {}^{2} - 2 } = 2a {}^{4n - 3} + a {}^{4 n - 3} \times (a {}^{2} - 2) = 2a {}^{4n - 3} + a {}^{4n - 1} - 2a {}^{4n - 3} = a {}^{4n - 1}$