Question

Реши уравнение
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Answer 1

$\frac{x^2-4}{2} - \frac{(x+1)(x-3)}{3} +x = \frac{(x-1)^2}{12}\\6x^2 - 24 - 4(x^2-2x-3)+12x = x^2-2x+1\\x^2+22x-13 = 0\\D/4 = 121 + 13 = 134\\x = -11\pm\sqrt{134}\\Answer: x = -11\pm\sqrt{134}$