Question

Помогите СРОЧНОО, ПОЖАЛУЙСТА.​

Answer 1

Ответ:

1) $\frac{2}{3a}$

2) $4x$

3) $\frac{3a+12}{a}$

Пошаговое объяснение:

1)

$(\frac{a-2}{a+2} - \frac{a+2}{a-2}) : \frac{12a^2}{4-a^2} = \frac{(a-2)^2-(a+2)^2}{(a+2)(a-2)} : \frac{12a^2}{4-a^2} = \frac{-4*2a}{(a+2)(a-2)} : \frac{12a^2}{4-a^2} = -\frac{8a}{(a+2)(a-2)} * \frac{4-a^2}{12a^2} = -\frac{2}{(a+2)(a-2)} * \frac{(2-a)(2+a)}{3a} = -\frac{2}{a-2} * \frac{-(a-2)*1}{3a} = -2*\frac{-1}{3a} = \frac{2}{3a}$

2)

$(\frac{8x}{x-2} +2x): \frac{3x+6}{6x-12} = \frac{8x+2x*(x-2)}{x-2} * \frac{6x-12}{3x+6} = \frac{8x+2x^2-4x}{x-2} * \frac{6(x-2)}{3(x+2)} = (4x+2x^2)*\frac{2}{x+2} = 2x*(2+x)*\frac{2}{x+2} = 2x*2 = 4x$

3)

$\frac{3a}{a-4} - \frac{a+2}{2a-8} * \frac{96}{a^2+2a} = \frac{3a}{a-4} - \frac{a+2}{2(a-4)} * \frac{96}{a(a+2)} = \frac{3a}{a-4} - \frac{1}{a-4} * \frac{48}{a} = \frac{3a}{a-4} - \frac{48}{a(a-4)} = \frac{3a^2-48}{a(a-4)} = \frac{3(a^2-16)}{a(a-4)} = \frac{3(a-4)(a+4)}{a(a-4)} = \frac{3(a+4)}{a} = \frac{3a+12}{a}$