Question

2x -4x=x(6x-3);
-8x² - 40x = 0;
x2 + x = 0;
- x² = - 67x;
- 4x² - 100 = 0; 2x2 = 0;
29x2 = 0;
2x - 242 = 0;

Answer 1

Ответ:

1) $2x-4x=x*(6x-3)$

$-2x=6x^2-3x$

$-2x-6x^2+3x=0$

$x-6x^2=0$

$x*(1-6x)=0$

$x=0$

$1-6x=0$

x₁ = 0 , x₂ = $\frac{1}{6}$

2) $-8x^2-40x=0$

$-8x*(x+5)=0$

$x*(x+5)=0$

$x=0$

$x+5=0$

x₁ = -5 , x₂ = 0

3) $x^2+x=0$

$x*(x+1)=0$

$x=0$

$x+1=0$

x₁ = -1 , x₂ = 0

4) $-x^2=-67x$

$-x^2+67x=0$

$-x*(x-67)=0$

$x*(x-67)=0$

$x=0$

$x-67=0$

x₁ = 0 , x₂ = 67

5) $-4x^2-100=0$

$x^2+25=0$

$x= \frac{-0\sqrt{0^2-4*1*25} }{2*1}$

$x=\frac{\sqrt{0-100} }{2}$

$x=\frac{\sqrt{-100} }{2}$

$x=\frac{10i}{2}$

$x=\frac{-10i}{2}$

x₁ = 5i , x₂ = -5i

6) $2x^2=0$

$x^2=0$

$x=0$

7) $29x^2=0$

$x^2=0$

$x=0$

8) $2x-242=0$

$2x=242$

$x=121$