Question

x³-x² если х=-2,х=0,1 решите пж​

Answer 1

Ответ:

${x}^{3} - {x}^{2} = {( - 2)}^{3} - {(0.1)}^{2} = - 8 - {( \frac{1}{10} )}^{2} = - 8 - \frac{1}{100} = \frac{ - 800 - 1}{100} = - \frac{801}{100} = - 8.01$