Question

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Answer 1

Ответ:

1)

$\frac{18 - 2a}{3a {}^{2} - 27 }$

2)

$\frac{3a + 12}{a}$

Объяснение:

1)

$( \frac{(a + 3)}{a - 3} + \frac{(a - 3)}{a + 3} ) \div \frac{3a {}^{2} + 27 }{9 - a {}^{2} } \\ \frac{(a + 3) {}^{2} + (a - 3) {}^{2} }{(a - 3) \times ( a + 3)} \times \frac{9 - a}{3a {}^{2} + 27 } \\ \frac{((a + 3) {}^{2} + (a - 3) {) \times (9 - a)}^{2} }{(a - 3) \times (a + 3) \times (3a {}^{2} + 27) } \\ \frac{(a {}^{2} + 6a + 9 + a {}^{2} - 6a + 9) \times (9 - a) }{(a {}^{2} - 9) \times 3(a {}^{2} + 9) } \\ \frac{(2a {}^{2} + 18) \times (9 - a) }{(a {}^{2} - 9) \times 3(a {}^{2} + 9) } \\ \frac{2(a {}^{2} + 9) \times (9 - a) }{(a {}^{2} - 9) \times 3(a {}^{2} + 9) } \\ \frac{2(9 - a)}{(a {}^{2} - 9) \times 3 } \\ \frac{18 - 2a}{3a {}^{2} - 27 }$

2)

$\frac{3a}{a - 4} - \frac{a + 2}{5a - 20} \times \frac{240}{a {}^{2} + 2a } \\ \frac{3a}{a - 4} - \frac{a + 2}{5(a - 4)} \times \frac{240}{a \times (a + 2)} \\ \frac{3a}{a - 4} - \frac{1}{a - 4} \times \frac{48}{a} \\ \frac{3a}{a - 4} - \frac{48}{a \times (a - 4)} \\ \frac{3a {}^{2} - 48 }{a \times (a - 4)} \\ \frac{3(a {}^{2} - 16) }{a \times (a - 4)} \\ \frac{3(a - 4) \times (a + 4)}{a \times (a - 4)} \\ \frac{3(a + 4)}{a} \\ \frac{3a + 12}{a}$